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JEE MAIN 2026 · Permutations and Combinations

JEE Main 2026 Session 2 Question Paper: 8 Apr, Shift 2 (B.E./B.Tech), question 9

Updated
Single correct+4 / -1Answer matches NTA’s final key

A person has three different bags and four different books. The number of ways, in which he can put these books in the bags so that no bag is empty, is:

Choose one

Solution

Solution

Count onto maps from 4 books to 3 bags by inclusion–exclusion:

34−(31)24+(32)14=81−48+3=36.3^4 - \binom31 2^4 + \binom32 1^4 = 81 - 48 + 3 = 36.

(Check another way: one bag gets two books, (42)=6\binom42 = 6 ways to pick them, then the three groups go into three distinct bags in 3!=63! = 6 ways: 3636.)

Answer: 36.

Answer checked against the official answer key. The solution is our own working.

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