Match List - I with List - II.
| List - I (Electronic configuration of neutral atom, where n = 2) | List - II (1st Ionization Energy, kJ mol⁻¹) | ||
|---|---|---|---|
| A. | ns² | I. | 2080 |
| B. | ns²np¹ | II. | 899 |
| C. | ns²np³ | III. | 800 |
| D. | ns²np⁶ | IV. | 1402 |
Choose the correct answer from the options given below:
Solution
Solution
With the atoms are Be (2s²), B (2s²2p¹), N (2s²2p³) and Ne (2s²2p⁶).
- Ne has a closed shell: the highest value, 2080 (I).
- N has a stable half-filled 2p subshell: 1402 (IV).
- Be loses an electron from a filled 2s subshell: 899 (II).
- B loses a single 2p electron, which is shielded by 2s and easier to remove than Be's: 800 (III). This is the familiar Be > B dip.
Answer: A-II, B-III, C-IV, D-I.
Answer checked against the official answer key. The solution is our own working.