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JEE MAIN 2026 · Electronic Devices

JEE Main 2026 Session 2 Question Paper: 8 Apr, Shift 2 (B.E./B.Tech), question 45

Updated
Single correct+4 / -1Answer matches NTA’s final key

The output YY for the given inputs AA and BB to the circuit is:

Input waveforms: A is 0 from 0 to 1 s and 1 from 1 s to 3 s; B is 1 from 0 to 2 s, 0 from 2 s to 3 s, then 1 again. Circuit: one AND gate takes A and B, a second AND gate takes B and the inverted A; both feed an OR gate whose output is Y

Choose one

Solution

Solution

Read the circuit. The upper AND gate receives AA and BB; the lower one receives BB and AA through an inverting bubble. So

Y=A⋅B+Aˉ⋅B=B(A+Aˉ)=B.Y = A\cdot B + \bar A \cdot B = B(A + \bar A) = B.

The output simply copies BB.

Read the waveform of BB. B=1B = 1 from 00 to 22 s, 00 from 22 to 33 s, and 11 again after 33 s. Checking interval by interval:

Interval AA BB YY
0–1 s 0 1 1
1–2 s 1 1 1
2–3 s 1 0 0

Answer: the graph that is high from 0 to 2 s and low from 2 to 3 s (option B).

Answer checked against the official answer key. The solution is our own working.

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